[Baekjoon/Python3] 9012번 괄호

[Baekjoon/Python3] 9012번 괄호

 

www.acmicpc.net/problem/9012

9012번: 괄호

 

t = int(input())
for i in range(t):
    s = list(input())
    cnt = 0
    for j in s:
        if j == '(':
            cnt += 1
        elif j == ')':
            cnt -= 1
        if cnt < 0:
            print('NO')
            break
    if cnt > 0:
        print('NO')
    elif cnt == 0:
        print('YES')